Oxidation and Reduction

Last updated: 7 October 2026

Diagnose → Learn → Master: Every study-note section includes 15 free MCQs — start with 5 Diagnostic MCQs to identify gaps in your understanding, then complete 10 Mastery MCQs near the end to check what you have learned.

Oxidation and reduction reactions are happening around us all the time. Magnesium burns in oxygen, iron rusts, fuels release energy when they burn and electrochemical cells produce electricity through redox reactions. These processes may look very different, but they are connected by the same underlying Chemistry.

The difficulty is that oxidation and reduction can be described in several different ways. In one reaction, the easiest clue may be the movement of oxygen. In another, oxygen may not appear at all, so electron transfer or oxidation states become much more useful.

Rather than memorising these as separate definitions, it is more useful to see them as different ways of describing the same paired process. Once that connection becomes clear, redox questions become much more logical.

Diagnostic quiz · 5 questions
What do you already know about redox?

Try these five questions before reading the chapter. They check the ideas that will make oxidation and reduction easier to understand.

  • Check your understanding of oxygen and electron transfer.
  • Spot common misconceptions before studying the chapter.
  • Read the explanation for every answer option.
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Oxidation and reduction always happen together

The word redox comes from the words reduction and oxidation. The name itself reminds us that these two processes are linked.

If one particle loses electrons, those electrons cannot simply disappear. Another particle must gain them. In the same way, if oxygen is transferred from one substance to another, one substance loses oxygen while the other gains it.

The paired-process principle

Oxidation and reduction occur together in a redox reaction. Whenever one substance is oxidised, another substance is reduced.

Consider the reaction between zinc and copper(II) ions:

Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

Zinc atoms lose electrons and become Zn²⁺ ions. Copper(II) ions gain those electrons and become copper atoms.

Zn(s) → Zn²⁺(aq) + 2e⁻
Cu²⁺(aq) + 2e⁻ → Cu(s)

The two electrons lost by zinc are exactly the same two electrons gained by Cu²⁺. Zinc is therefore oxidised while Cu²⁺ is reduced.

Oxidation and reduction in terms of oxygen

The simplest redox reactions to recognise are often those involving oxygen. Compare each reactant with the product that it forms and ask whether oxygen has been gained or lost.

Oxidation: gain of oxygen.

Reduction: loss of oxygen.

Example: copper(II) oxide reacting with hydrogen

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

Copper(II) oxide, CuO, becomes copper. CuO has therefore lost oxygen, so CuO has been reduced.

Hydrogen, H₂, becomes water. Hydrogen has gained oxygen, so hydrogen has been oxidised.

ReactantWhat happens?Conclusion
CuOLoses oxygen and forms CuReduced
H₂Gains oxygen and forms H₂OOxidised
Compare the complete substances

It is more precise to say that CuO is reduced to Cu than simply to write that “copper is reduced”. Copper(II) oxide is the reactant undergoing reduction.

Example: magnesium burning in oxygen

2Mg(s) + O₂(g) → 2MgO(s)

Magnesium gains oxygen and forms magnesium oxide. Magnesium has therefore been oxidised.

The oxygen definition is useful, but it cannot explain every redox reaction because many redox reactions contain no oxygen.

Oxidation and reduction in terms of hydrogen

Redox changes can also be recognised by following hydrogen. The hydrogen definitions are the opposite of the oxygen definitions.

Oxidation: loss of hydrogen.

Reduction: gain of hydrogen.

Example: hydrogen sulfide reacting with chlorine

H₂S(g) + Cl₂(g) → 2HCl(g) + S(s)

H₂S becomes sulfur. It has lost hydrogen, so H₂S has been oxidised.

Cl₂ becomes HCl. Chlorine has gained hydrogen, so chlorine has been reduced.

ReactantWhat happens?Conclusion
H₂SLoses hydrogenOxidised
Cl₂Gains hydrogenReduced

Oxygen and hydrogen transfer are useful when these atoms can be followed directly. However, a more general definition is needed for reactions where neither oxygen nor hydrogen is transferred.

Oxidation and reduction in terms of electrons

Electron transfer gives us a more general description of redox. Instead of following oxygen or hydrogen atoms, we look at what happens to the electrons of the reacting particles.

Oxidation: loss of electrons.

Reduction: gain of electrons.

Remember OIL RIG

A useful memory aid is OIL RIG:

  • Oxidation Is Loss of electrons.
  • Reduction Is Gain of electrons.

The idea also makes sense from charge. Electrons are negatively charged. Losing electrons makes a particle more positive, while gaining electrons makes it less positive or more negative.

Example: zinc loses electrons

Zn(s) → Zn²⁺(aq) + 2e⁻

Zinc starts as a neutral atom. To form Zn²⁺, it must lose two negatively charged electrons.

Zn loses electrons → oxidation

Example: copper(II) ions gain electrons

Cu²⁺(aq) + 2e⁻ → Cu(s)

A Cu²⁺ ion gains two electrons and becomes a neutral copper atom.

Cu²⁺ gains electrons → reduction
Electron transfer from zinc to copper(II) ions showing zinc losing two electrons and being oxidised while copper(II) ions gain two electrons and are reduced
The electrons lost by zinc are gained by Cu²⁺, so oxidation and reduction occur together.
The electrons must balance

The total number of electrons lost during oxidation must equal the total number of electrons gained during reduction. Electrons are transferred; they are not created or destroyed.

Using oxidation states to recognise redox

Electrons are not normally written in an overall chemical equation. Oxidation states, also called oxidation numbers, give us another way to track the same changes.

Oxidation: increase in oxidation state.

Reduction: decrease in oxidation state.

Useful rules for oxidation states

RuleExample
An element in its uncombined state has oxidation state 0. Zn, H₂, O₂ and Cl₂ all have oxidation state 0.
The oxidation state of a simple ion is equal to its charge. Na⁺ is +1, Mg²⁺ is +2 and Cl⁻ is −1.
Hydrogen is usually +1 in its compounds. H is +1 in H₂O.
Oxygen is usually −2 in its compounds. O is −2 in CuO and CO₂.
Oxidation states in a neutral compound add up to 0. The oxidation states in H₂O add up to 0.

Worked example: oxidation state of sulfur in SO₂

Oxygen normally has oxidation state −2.

There are two oxygen atoms, so their total oxidation state is:

2 × (−2) = −4

SO₂ is neutral, so all oxidation states must add up to zero. Let the oxidation state of sulfur be x.

x + (−4) = 0
x = +4

Sulfur therefore has oxidation state +4 in SO₂.

Identifying redox using oxidation-state changes

Return to the zinc–copper reaction:

Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
ElementBeforeAfterConclusion
Zn0+2 Oxidation state increases → oxidation
Cu+20 Oxidation state decreases → reduction
Why does an increasing oxidation state mean oxidation?

Zinc changes from 0 to +2 because it loses two negatively charged electrons. An increase in oxidation state therefore corresponds to electron loss.

What do Roman numerals in chemical names mean?

Some metals can form ions with more than one charge. Roman numerals in their names show the oxidation state of the metal.

FormulaOxidation state of ironName
FeCl₂+2Iron(II) chloride
FeCl₃+3Iron(III) chloride

The Roman numeral does not tell you how many metal atoms are present. Iron(III), for example, means that iron has oxidation state +3.

Not every chemical reaction is redox

Oxidation states are also useful for deciding whether a reaction is redox at all.

Consider an acid–alkali neutralisation:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

None of the elements changes oxidation state. This is an acid–base reaction, not a redox reaction.

Similarly:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

The oxidation states remain unchanged. This is a precipitation reaction, not a redox reaction.

When in doubt, compare oxidation states

A redox reaction must contain an increase in oxidation state and a decrease in oxidation state. If no oxidation states change, the reaction is not redox.

Oxidising and reducing agents

The terms oxidising agent and reducing agent often cause confusion because the name tells you what the substance does to the other reactant.

AgentWhat it doesElectron behaviourWhat happens to the agent?
Oxidising agentCauses another substance to be oxidisedAccepts electronsIt is reduced
Reducing agentCauses another substance to be reducedDonates electronsIt is oxidised
Comparison of reducing and oxidising agents showing that a reducing agent donates electrons and is oxidised while an oxidising agent accepts electrons and is reduced
A reducing agent donates electrons and is itself oxidised, while an oxidising agent accepts electrons and is itself reduced.

Identifying the agents in a reaction

Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

Zinc loses electrons:

Zn → Zn²⁺ + 2e⁻

Zinc supplies the electrons needed to reduce Cu²⁺. Zinc is therefore the reducing agent. Zinc itself is oxidised.

Copper(II) ions gain electrons:

Cu²⁺ + 2e⁻ → Cu

Cu²⁺ accepts electrons and causes zinc to lose them. Cu²⁺ is therefore the oxidising agent. Cu²⁺ itself is reduced.

Substance oxidised → reducing agent

Substance reduced → oxidising agent

The agent undergoes the opposite process

An oxidising agent causes oxidation but is itself reduced. A reducing agent causes reduction but is itself oxidised.

Testing for oxidising and reducing agents

Redox behaviour can also be investigated experimentally. At O-Level, two important tests involve acidified potassium manganate(VII) and aqueous potassium iodide.

Testing for a reducing agent

Add acidified potassium manganate(VII) solution to the substance being tested.

Positive result: the purple solution is decolourised.

A reducing agent donates electrons. Manganate(VII) ions accept these electrons and are reduced, so the purple colour disappears.

State the colour change precisely

Write that the purple solution is decolourised. Avoid vague descriptions such as “the colour becomes lighter”.

Testing for an oxidising agent

Add aqueous potassium iodide to the substance being tested.

Positive result: the colourless solution turns brown because iodine is formed.

An oxidising agent removes electrons from iodide ions, I⁻. The iodide ions are therefore oxidised to iodine.

2I⁻(aq) → I₂(aq) + 2e⁻

The iodine formed gives the mixture its brown colour.

Testing forReagentPositive observationWhat happens?
Reducing agentAcidified potassium manganate(VII)Purple solution is decolourisedManganate(VII) ions are reduced
Oxidising agentAqueous potassium iodideColourless solution turns brownIodide ions are oxidised to iodine

Which redox definition should you use?

All four definitions describe redox, but some are more useful than others for a particular reaction.

What can you see in the reaction?Useful approach
Oxygen moves between substancesGain or loss of oxygen
Hydrogen moves between substancesGain or loss of hydrogen
Electron transfer or ionic charge changes are clearLoss or gain of electrons
No obvious transfer is visibleIncrease or decrease in oxidation state

Always pay attention to the wording of the examination question. If the question asks you to explain oxidation in terms of electron transfer, saying only that oxygen is gained does not directly answer what was asked.

Common mistakes with oxidation and reduction

Common mistakeWhy it is wrongCorrect approach
Thinking oxidation always involves oxygen Many redox reactions contain no oxygen Use electron transfer or oxidation-state changes when appropriate
Saying that loss of electrons is reduction Loss of electrons is oxidation Remember OIL RIG
Saying only “copper is reduced” in CuO + H₂ → Cu + H₂O CuO is the reactant undergoing reduction State that copper(II) oxide is reduced to copper
Using the 2 in O₂ as the oxidation state of oxygen The subscript tells you the number of atoms An uncombined element has oxidation state 0
Thinking the oxidising agent is the substance being oxidised The oxidising agent is itself reduced Identify what happens to each reactant before naming the agent
Thinking the reducing agent is the substance being reduced A reducing agent donates electrons and is itself oxidised The substance oxidised is the reducing agent
Using acidified potassium manganate(VII) as the test for an oxidising agent It is used to test for a reducing agent A reducing agent decolourises the purple manganate(VII) solution
Writing only “turns colourless” for the manganate(VII) test A complete observation should include the initial colour State that the purple solution is decolourised
Assuming every chemical reaction is redox Neutralisation and precipitation can occur without oxidation-state changes Check whether oxidation states increase and decrease
Summary comparing oxidation and reduction in terms of oxygen transfer, hydrogen transfer, electron transfer and changes in oxidation state
Four complementary ways to recognise oxidation and reduction.

Oxidation and reduction checklist

Recognise oxidation

  • Gain of oxygen.
  • Loss of hydrogen.
  • Loss of electrons.
  • Increase in oxidation state.

Recognise reduction

  • Loss of oxygen.
  • Gain of hydrogen.
  • Gain of electrons.
  • Decrease in oxidation state.

Identify the agents

  • Identify which reactant is oxidised.
  • That reactant is the reducing agent.
  • Identify which reactant is reduced.
  • That reactant is the oxidising agent.

Remember the laboratory tests

  • Reducing agent: acidified potassium manganate(VII).
  • Purple solution is decolourised.
  • Oxidising agent: aqueous potassium iodide.
  • Colourless solution turns brown as iodine forms.
Mastery quiz · 10 questions
Can you apply oxidation and reduction?

Now apply the chapter to equations, oxidation states, redox agents and laboratory observations.

  • Apply several definitions of oxidation and reduction.
  • Identify oxidising and reducing agents.
  • Interpret oxidation states and laboratory redox tests.
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Questions students often ask about oxidation and reduction

These questions connect the different definitions of redox and clear up several ideas that commonly cause confusion.

Can oxidation happen without oxygen?

Yes. The oxygen definition is only one way of recognising oxidation. Oxidation can also be defined as loss of electrons or an increase in oxidation state.

For example, in Zn + Cu²⁺ → Zn²⁺ + Cu, zinc is oxidised even though oxygen is not involved.

Why must oxidation and reduction happen together?

If one particle loses electrons, another particle must accept those electrons. Electrons cannot simply disappear.

The number of electrons lost during oxidation must therefore equal the number gained during reduction.

Why does losing electrons make a particle more positive?

Electrons have negative charge. When an atom loses negative charge, it becomes more positive.

For example, Zn → Zn²⁺ + 2e⁻ shows a zinc atom losing two electrons to form a 2+ ion.

Does a positive oxidation state mean that oxidation has occurred?

Not necessarily. Oxidation is identified from a change in oxidation state.

A change from 0 to +2 is oxidation because the oxidation state has increased. Simply knowing that an element has oxidation state +2 does not tell you whether oxidation has just occurred.

Why is an oxidising agent itself reduced?

An oxidising agent causes another substance to lose electrons by accepting those electrons itself.

Since gain of electrons is reduction, the oxidising agent is itself reduced.

Why is a reducing agent itself oxidised?

A reducing agent causes another substance to gain electrons by supplying those electrons.

Since the reducing agent loses electrons, it is oxidised. The name describes what the agent does to the other reactant.

Do Roman numerals show how many metal atoms are present?

No. A Roman numeral shows the oxidation state of the named element. Iron(II) chloride contains iron in oxidation state +2, whereas iron(III) chloride contains iron in oxidation state +3.

The subscripts in a chemical formula show the relative numbers of atoms or ions.

How can I tell whether an unfamiliar reaction is redox?

Compare the oxidation states of the relevant elements in the reactants and products.

If one oxidation state increases while another decreases, oxidation and reduction have both occurred. If no oxidation states change, the reaction is not redox.

Why does acidified potassium manganate(VII) test for a reducing agent?

A reducing agent donates electrons. The manganate(VII) ions accept these electrons and are reduced.

As this happens, the purple acidified potassium manganate(VII) solution is decolourised.

Why does potassium iodide turn brown in the presence of an oxidising agent?

An oxidising agent removes electrons from iodide ions:

2I⁻ → I₂ + 2e⁻

Iodine is formed and gives the mixture its brown colour.

Are combustion reactions redox reactions?

Yes. During combustion, the substance being burned is oxidised while oxygen is reduced.

For example, when magnesium burns, magnesium changes from oxidation state 0 to +2 while oxygen changes from 0 to −2.

Is rusting a redox process?

Yes. During rusting, iron is oxidised while oxygen is reduced. Water is also required for rusting to occur readily.

Oxidation and reduction become much easier once the different definitions are seen as connected rather than memorised separately. Gain of oxygen, loss of hydrogen, loss of electrons and an increase in oxidation state all point towards oxidation; the opposite changes point towards reduction. Once you can track these changes confidently, identifying redox reactions, oxidising and reducing agents and laboratory redox tests becomes a logical process rather than a collection of unrelated facts.

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